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江苏省南京市建邺区八年级上期中数学试卷及答案(批量下载)

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公众号:惟微小筑

南京市建邺区2021-2021学年度第|一学期期(中|考)试八年级|数学试卷

(考试时间100分钟, 试卷总分100分 )

一、选择题 (本大题共6小题, 每题2分, 共12分 ) 1.在下面的四个京剧脸谱中, 不是轴对称图形的是 ( ▲ )

A.

B.

C.

D.

2.以下长度的三条线段能组成直角三角形的是 ( ▲ ) A.1, 2, 3

B.2, 3, 4

C.3, 4, 5

D.5, 6, 7

3.等腰三角形两边长分别为2和4, 那么这个等腰三角形的周长为 ( ▲ ) A.6

B.8

C.10

D.8或10

4.如图, 在数轴上表示实数7+1的点可能是 ( ▲ ) A.P

B.Q

A'

O

C.R

B

D.S

D C

H P Q R S A B'

0 1 2 3 4 5 A C B

(第4题 ) (第5题 ) (第6题 )

5.如图是跷跷板的示意图, 支柱OC与地面垂直, 点O是AB的中点, AB绕着点O上下转动.当A端落地时, ∠OAC=20°, 跷跷板上下可转动的最|大角度 (即∠A′OA )是 ( ▲ ) A.20°

B.40°

C.60°

D.80°

6.如图, 在四边形ABCD中, AB=AC=BD, AC与BD相交于H, 且AC⊥BD.

①AB∥CD;②△ABD≌△BAC;③AB2+CD2=AD2+CB2;④∠ACB+∠BDA=135°.其中真命题的个数是 ( ▲ ) A.1

B.2

C.3

D.4

二、填空题 (本大题共10小题, 每空2分, 共20分 ) 7.5的相反数是 ▲ .

8.一个罐头的质量约 kg, kg可得近似值 ▲ kg.

9.如图, 点A, D, C, F在同一条直线上, AB=DE, ∠B=∠E, 要使△ABC≌△DEF, 还需要添加一个条件是 ▲ .

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B 10.如图, 在Rt△ABC中, CD是斜边AB上的中线, 假设AB=2, 那么CD= ▲ . B

E

B

A D (第9题 )

C F C D D

A A (第10题 )

E F C (第11题 )

11.如图, 在△ABC中, AB=AC, ∠B=66°, D, E分别为AB, BC上一点, AF∥DE, 假设∠BDE

=30°, 那么∠FAC的度数为 ▲ .

12.如图, 一块形如 \"Z〞字形的铁皮, 每个角都是直角, 且AB=BC=EF=GF

=1, CD=DE=GH=AH=3, 现将铁片裁剪并拼接成一个和它等面积的正方形, 那么正方形的边长是 ▲ .

13.如图, △ABC, △ADE均是等腰直角三角形, BC与DE相交于F点, 假设AC

=AE=1, 那么四边形AEFC的周长为 ▲

D

(第12题 )

A

A B C G F

E

B

(第13题 ) E

F C D

B

D (第14题 )

C

H E

A

14.如图, △ABC是边长为6的等边三角形, D是BC上一点, BD=2, DE⊥BC交AB于点E,

那么AE= ▲ .

A ABC的角平分线A 15.如图, 在△ABC中, AB=4, AC=3, BC=5, AD是△, DE⊥AB于点E, 那

么DE长是 ▲ . A

B

D (第15题 )

C C

B

E E P

D

C B

(第16题 )

16.如图, 在△ABC中, ∠C=90°, ∠A=34°, D, E分别为AB, AC上一点, 将△BCD, △

ADE沿CD, DE翻折, 点A, B恰好重合于点P处, 那么∠ACP= ▲ .

三、解答题 (本大题共10题, 共68分 )

17. (6分 )计算

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(1 )(-2)+64-4; (2 )

2

3

9

1+(π-3)0-|1-3|. 16

18. (6分 )求以下各式中的x

(1 )(x+2)2=4; (2 )1+(x-1)3=-7.

19. (6分 )请在以下图中画出三个以AB为腰的等腰△ABC.

(要求:1.锐角三角形, 直角三角形, 钝角三角形各画一个;2.点C在格点上.)

A B

A B

A B

(锐角三角形 ) (直角三角形 )

(钝角三角形 )

20. (6分 )如图, AC⊥BC, BD⊥AD, 垂足分别为C, D, AC=BD.求证BC=AD. D C

A B

(第20题 )

21. (6分 )如图, 在△ABC中, 边AB, AC的垂直平分线相交于点P.求证PB=PC.

P

B

(第21题 )

C

A

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22. (6分 )如图, 点P为△ABC边BC上一点.请用直尺和圆规作一条直线EF, 使得

A关于EF的对称点为P. (保存作图痕迹, 不写作法 )

23. (7分 )如图, 在长方形ABCD中, AB=8, AD=10, 点E为BC上一点, 将△ABE沿AE

折叠, 使点B落在长方形内点F处, 且DF=6, 求BE的长.

A 24. (8分 )如图, 在△ABC中, AB=AC, ∠A=48°, 点D、E、F分别在BC、AB、AC边上,

且BE=CF, BD=CE, 求∠EDF的度数.

B

E

(第24题 )

B

E (第23题 )

F

A

D

A (第22题 )

B

P C C

D F C

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25. (8分 )阅读理解:求107的近似值.

解:设107=10+x, 其中0<x<1, 那么107=(10+x)2, 即107=100+20x+x2.

因为0<x<1, 所以0<x2<1, 所以107≈100+20x, 解之得x≈, 即107的近似值为10.35.

理解应用:利用上面的方法求97的近似值 (结果精确到0.01 ).

26. (9分 )如图, 在四边形ABCD中, AB∥CD, ∠D=90°, 假设AD=3, AB=4, CD=8, 点P

为线段CD上的一动点, 假设△ABP为等腰三角形, 求DP的长.

A B

D (第26题 )

C

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D (备用图3 )

C

A

B

D (备用图2 )

C

A

B

D (备用图1 )

C

A

B

南京市建邺区2021-2021学年度第|一学期期中学情试卷

八年级|数学参考答案及评分标准

说明:本评分标准每题给出了一种或几种解法供参考, 如果考生的解法与本解答不同, 参照本评分标准的精神给分.

一、选择题 (每题2分, 共计12分 )

题号 答案 1 D 2 C 3 C 4 B 5 B 6 B

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二、填空题 (每题2分, 共计20分 ) 7.-5. 12.10.

三、解答题 (本大题共10小题, 共计68分 ) 17.(此题6分)

解: (1 )(-2)+64-4

=4+4-2

=6 ······························································································· 3分 (2 )

91+(π-3)0-|1-3| 16

5

= +1-(3-1) 4

13

=-3. ·················································································· 6分

4

18.(此题6分)

解: (1 )x-2=±2 ··················································································· 1分 x=±2+2

x=0, x2=4. ··············································································· 3分

(2 )(x-1)3=-8 ··················································································· 4分 x-1=-2 ··················································································· 5分

x=-1. ····················································································· 6分

19.(此题6分)图略.

20.(此题6分)

证明:∵ AC⊥BC, BD⊥AD, ∴ ∠C=∠D=90°.

在Rt△ABC和Rt△BAD中,

AB=BA

AC=BD.

2

8.. 13.22.

9.BC=EF (答案不惟一 ). 14.2.

10.1. 12

15..

7

11.18. 16.22.

3

∴ Rt△ABC≌Rt△BAD(HL).

∴ BC=AD. ························································································· 6分

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21.(此题6分)

证明:∵ 边AB, AC的垂直平分线相交于点P, ∴ PA=PB, PA=PC.

∴ PB=PC. ················································································ 6分

22.(此题6分)图略.

23.(此题7分)

解:∵ 将△ABE沿AE折叠, 使点B落在长方形内点F处,

∴ ∠AFE=∠B=90°, AB=AF=8, BE=FE. 在△ADF中, ∵ AF2+DF2 =62+82 =100 =102=AD2,

B

E

F

C

A D

∴ △ADF是直角三角形, ∠AFD=90°. ····················································· 3分 ∴ D, F, E在一条直线上. ····································································· 4分 设BE=x, 那么EF=x, DE=6+x, EC=10-x, 在Rt△DCE中, ∠C=90°, ∴ CE2+CD2=DE2, 即 (10-x) 2+82=(6+x) 2. ∴ x=4.

∴ BE=4. ··························································································· 7分

24.(此题8分)

(1 )证明:∵ AB=AC, ∠A=48°,

∴ ∠B=∠C=(180°-48°)÷2=66°. ················································ 2分 在△DBE和△ECF中,

A D BD=CE

∠B=∠C BE=CF.

∴ ∠FEC=∠BDE,

∴ ∠DEF=180°-∠BED-∠FEC

F ∴ △DBE≌△ECF(SAS). ································································· 4分

B

E

C

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=180°-∠DEB-∠EDB=∠B=66°. ············································· 6分 ∵ △DBE≌△ECF(SAS),

∴ DE=FE.∴△DEF是等腰三角形.

∴ ∠EDF =(180°-66°)÷2=57°. ···················································· 8分

25.(此题8分)

解:设97=10-x, 其中0<x<1, 那么97=(10-x)2, 即97=100-20x+x2.

因为0<x<1, 所以0<x2<1,

所以97≈100-20x, 解之得x≈0.15, 即97的近似值为9.85. ··························· 8分 (设97=9+x, 求出97的近似值为9.89也给总分值.)

26.(此题9分)

解:①AB=AP时, DP1=4-3=7; ·························································· 2分

11②BP=AP时, DP2=AB=×4=2; ························································· 4分

22③BA=BP时, 过点B作BH⊥CD于H, 那么BH=AD=3, 由勾股定理得, FP=4-3=7, DP3=4-7, 或者DP4=4+7.

综上所述, DP的值为7, 2, 4-7, 或者4+7. ········································ 9分

A

B

2222D P3 P2 P1 H P4 C

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